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OnCommand Report temporary license URL Broken?

Looking to get a temporary OnCommand Report license until our Sales rep comes through on the zero dollar, but the page for the temporary license is out of commision it appears.  Anyone know how to get this temp license now?

thanks.

Re: OnCommand Report temporary license URL Broken?

Hi,

The below link can be used to request for an evaluation license. Select OnCommand Report in the “ Select a Product” Field.

https://communities.netapp.com/community/netapp_partners_network/storage_management_software/oncommandinsight?view=overview

This link was accessible for me. In case, the link is still not accessible, send a direct message to me with the customer name.I can help on this.

Thanks,

Yuvaraju

Re: OnCommand Report temporary license URL Broken?

I am also looking for a temporary license for OnCommand Report and I receive an Unauthorized page. Is there a way round this

Re: OnCommand Report temporary license URL Broken?

Re: OnCommand Report temporary license URL Broken?

Thank you but when I go to that page I receive:

Unauthorized

Welcome to the NetApp Communities site, where you can find and share ideas with other technical experts in our open forums. Registration for this community site is free and easy, so please sign up today. If you already have a NetApp Community profile, you may login here

I've already signed up and when I click the login here I get a Jive error page at

https://communities.netapp.com/jive_saml_login

Am I doing something wrong?

Re: OnCommand Report temporary license URL Broken?

I believe that page is for NetApp employees and partners only. I had access as a NetApp employee, but not with an end user account. Now I have a partner login it is again accessible. It would probably faster to talk to an SE or partner you trust and get them to request one for you. Thats what I ended up doing and it took a day or two to get it. However, my full $0 licence seems to have got lost in the post. :-)

Re: OnCommand Report temporary license URL Broken?

Thanks for your help.